Asked by Morgan
Find the angle, in degrees, between two adjacent sides of the pyramid.
P(2, 0, 0), Q(2, 2, 0), R(0, 2, 0), (base points)
S(1, 1, 7) (tip point)
P(2, 0, 0), Q(2, 2, 0), R(0, 2, 0), (base points)
S(1, 1, 7) (tip point)
Answers
Answered by
oomath
use cross product to get one side (n1)
n1= 2,0,0 x 1,1,7 = 0,-14, 2
use cross product to get another side (n2)
n2 = 0,2,0 x 1,1,7 = 14,0,-2
cos theta = (n1 x n2) / sqrt(sum of n1square) x sqrt(sum of n2 squares
-4 / sqrt(196+4) x sqrt(196+4)
-4/200
cos theta = - .02
theta = arccos (-.02) = 91.1
n1= 2,0,0 x 1,1,7 = 0,-14, 2
use cross product to get another side (n2)
n2 = 0,2,0 x 1,1,7 = 14,0,-2
cos theta = (n1 x n2) / sqrt(sum of n1square) x sqrt(sum of n2 squares
-4 / sqrt(196+4) x sqrt(196+4)
-4/200
cos theta = - .02
theta = arccos (-.02) = 91.1
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