Asked by ayan
a foot ball is thrown upward with an angle of 30 degree with respect to the horizantal .to throw a 40meter pass what must be the intial speed of the ball?
Answers
Answered by
bobpursley
horizonal distance=vcos30*time
time=40/vcos30
time in air:
hf=hi+viSin30*t-4.9t^2
hf, hi is zero.
0=v/2 (40/Vcos30)-4.9(40/vcos30)^2
solve for v.
time=40/vcos30
time in air:
hf=hi+viSin30*t-4.9t^2
hf, hi is zero.
0=v/2 (40/Vcos30)-4.9(40/vcos30)^2
solve for v.
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