Asked by Steven
The speed of the car at the base of a 30 ft hill is 45 mi/h. Assuming the driver keeps her foot off the brake and accelerator pedals, what will be the speed of the car at the top of the hill?
Answers
Answered by
Don
Kinetic energy + Potential Energy
(1/2) *m*vf^2 + (1/2)*m*vi^2 = mgh
m=mass
but we we really don't need the mass to figure this problem out since we can factor it out of the equation
Now isolate the vf
vf = sqrt(2*g*h - vi^2)
g=9.81
h=30
vi=45
vf=sqrt(2*9.81*30 - 45^2)
vf=37.899
Can someone check this????? really not sure just gave it a go
(1/2) *m*vf^2 + (1/2)*m*vi^2 = mgh
m=mass
but we we really don't need the mass to figure this problem out since we can factor it out of the equation
Now isolate the vf
vf = sqrt(2*g*h - vi^2)
g=9.81
h=30
vi=45
vf=sqrt(2*9.81*30 - 45^2)
vf=37.899
Can someone check this????? really not sure just gave it a go
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