Asked by Jil
Katie kicks a football at a 52 degree angle and a velocity of 31 m/s. At what times will it be 10 meters off the ground?
Answers
Answered by
Henry
Vo = 31m/s[52o]
Yo = 31*sin52 = 34.4 m/s.
h = Yo*t + 0.5g*t^2 = 10 m.
34.4*t - 4.9t^2 = 10
-4.9t^2 + 34.4t - 10 = 0
Use Quadratic formula and get:
t1 = 0.304 s.
t2 = 6.71 s.
Yo = 31*sin52 = 34.4 m/s.
h = Yo*t + 0.5g*t^2 = 10 m.
34.4*t - 4.9t^2 = 10
-4.9t^2 + 34.4t - 10 = 0
Use Quadratic formula and get:
t1 = 0.304 s.
t2 = 6.71 s.
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