Question
A force of 3.25 N acts on a(n) 3.8 kg object
for 16.5 s. What is the object’s change in
momentum?
for 16.5 s. What is the object’s change in
momentum?
Answers
Don
F=ma
F=Force
m=mass
a=acceration
F/m = a
3.25/3.8 = .855m/s^2
a=.855 m/s^2
now we have to find velocity at given time
a*t=v
.855*16.5 = 14.11 m/s
now momentum formula
p=m*v
p=momentum
m=mass
v=velocity
p=3.8*14.11
= 53.616 Ns
Someone check my work.
F=Force
m=mass
a=acceration
F/m = a
3.25/3.8 = .855m/s^2
a=.855 m/s^2
now we have to find velocity at given time
a*t=v
.855*16.5 = 14.11 m/s
now momentum formula
p=m*v
p=momentum
m=mass
v=velocity
p=3.8*14.11
= 53.616 Ns
Someone check my work.