Asked by Taylor
A mixture containing 2.81 g each of CH4 (g), C2H4 (g) and C4H10 (g) is contained in a 1.50 L flask at a temperature of 35 oC. What is the partial pressure (in atm) of C4H10 (g)?
Answers
Answered by
bobpursley
figure the moles of each, then total moles.
PV=totalmales*RT
solve for pressure p
then
partial pressure=p * moleC4H10/totalmoles
PV=totalmales*RT
solve for pressure p
then
partial pressure=p * moleC4H10/totalmoles
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