A mixture containing 2.81 g each of CH4 (g), C2H4 (g) and C4H10 (g) is contained in a 1.50 L flask at a temperature of 35 oC. What is the partial pressure (in atm) of C4H10 (g)?

Answer 1

figure the moles of each, then total moles.

PV=totalmales*RT
solve for pressure p

then
partial pressure=p * moleC4H10/totalmoles