Asked by hakan
Stones are thrown horizontally with the same velocity from two buildings. One stone lands 1.81 as far away from its building as the other stone. Determine the ratio of the heights of the two buildings.
Answers
Answered by
Damon
time 2 = 1.81 * time 1
h = (1/2)gt^2
so
h/t^2 = constant = H1/t1^2 = H2/t2^2
H2/H1 = t2^2/t1^2 = 1.81^2 = 3.27
h = (1/2)gt^2
so
h/t^2 = constant = H1/t1^2 = H2/t2^2
H2/H1 = t2^2/t1^2 = 1.81^2 = 3.27
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