Asked by Airisse
Show that the equation
sqrt((x-c)^2 + y^2)+sqrt((x+c)^2 + y^2) = 2a
can be simplified to
(x^2/a^2) + (y^2/b^2) = 1
where b^2 = a^2-c^2.
sqrt((x-c)^2 + y^2)+sqrt((x+c)^2 + y^2) = 2a
can be simplified to
(x^2/a^2) + (y^2/b^2) = 1
where b^2 = a^2-c^2.
Answers
Answered by
Steve
Draw a diagram of an ellipse. Draw diagonals from (0,b) to (-c,0) and (c,0)
The definition of such an ellipse is that the sum of the distances from a point to the foci is constant, and = 2a where a,b,c are described above.
Just google any explanation of the definition of an ellipse, its foci, and eccentricity.
The definition of such an ellipse is that the sum of the distances from a point to the foci is constant, and = 2a where a,b,c are described above.
Just google any explanation of the definition of an ellipse, its foci, and eccentricity.
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