Asked by Jay
How long would it take a 4.50-kW motor to raise a 175-kg boiler to a platform 15.0 m
above the floor?
Is this correct?
175*9.80*15.0/4.50
above the floor?
Is this correct?
175*9.80*15.0/4.50
Answers
Answered by
Henry
F = m*g = 175 * 9.8 = 1715 N. = Force of
the boiler.
Work = F*d = 1715 * 15 = 25,725 J.
4.5kw = 4500 W. = 4500J/s.
t = 25,725J. * 1s/4500J = 5.72 s.
the boiler.
Work = F*d = 1715 * 15 = 25,725 J.
4.5kw = 4500 W. = 4500J/s.
t = 25,725J. * 1s/4500J = 5.72 s.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.