Asked by Aluminum<3 Helping and C.S.I

Hi I'm Aluminum<3 Helping and C.S.I, but you can call me Alumi. for short.

So here's my Question,Determine how many solutions exist for the system of equations.
I need someone who can WORK IT OUT with me and SHOW me how to do it.

1. 6x+y=−3
2. 6x+y=−3
They both have these 3 options as answers.
A. One solution
B. Infinite solutions
C. No solutions

Thank You.
Cheers,

Alumi.
Answered by Aluminum<3 Helping and C.S.I
Oh and thanks, I really struggle in this.
Answered by Aluminum<3 Helping and C.S.I
@ Brady, @ Ay!!, @ Ms. Sue, @ Anonymous :D,
Answered by Aluminum<3 Helping and C.S.I
PLEASE HELP MEH!!!! I"M IN A HURRY>
Answered by Matt
infinate

if x=1, then
6(1)+y=-3
6+y=-3
move the six
y=-3+(-6)
y=-9

or
if x=-2, then
6(-2)+y=-3
-12+y=-3
subtract the twelve and add to the other side
y=-3+(--12)
two neg = positive
thus y=-3 + 12
y=9
Answered by Ms. Sue
Please be patient. All tutors are volunteers, and sometimes a tutor may not be immediately available. Please be patient while waiting for a response to your question.
Answered by Matt
*infinite
Answered by Aluminum<3 Helping and C.S.I
I'm sorry Ms. Sue. :(
On the other hand though.


Thanks A MILLION @ Matt!!!!
Answered by Aluminum<3 Helping & C.S.I ♪♫
@ Ms. sue, changing name again. Gonna b


Alumi.♪♫
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