I = E/5R = 9.74 Amps
E = 5R * 9.74 = 48.7R
I = E/6R = 48.7R/6R = 8.12 Amps.
Five identical resistors, each of resistance R, are connected in series to a battery, and a total current of 9.74 A flows in the circuit.
i. Now, another resistor of resistance R is added to the circuit, in series with the rest of the resistors. Find the new total current in the circuit. I =
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