A volume of 60.0mL of aqueous potassium hydroxide (KOH) was titrated against a standard solution of sulfuric acid (H2SO4). What was the molarity of the KOH solution if 19.2mL of 1.50 M H2SO4 was needed? The equation is

Question

2KOH(aq)+H2SO4(aq)→K2SO4(aq)+2H2O(l)
Express the molar concentration numerically.

Answer 1

mols H2SO4 = M x L = ?
Using the coefficients in the balanced equation, convert mols H2SO4 to mols NaOH.
Then M NaOH = mols NaOH/L NaOH

Answer 2

0.96mol/L