Asked by Leah
If a ball is thrown vertically upward from the roof of 48 foot building with a velocity of 80 ft/sec, its height after t seconds is s(t) = 48+80t-16t^2
What is the velocity of the ball when it hits the ground?
What is the velocity of the ball when it hits the ground?
Answers
Answered by
Henry
When the ball returns to the roof, its
velocity will be 80 Ft/s.
V^2 = Vo^2 + 2g*h = 80^2 + 64*48 = 9472
V = 97.32 Ft/s.
velocity will be 80 Ft/s.
V^2 = Vo^2 + 2g*h = 80^2 + 64*48 = 9472
V = 97.32 Ft/s.
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