Asked by Ashley
Find a number such that the sum of two times the number and six times its reciprocal is 79/5.
Answers
Answered by
Steve
2x + 6/x = 79/5
10x^2 + 30 = 79x
10x^2 - 79x + 30 = 0
(5x-2)(2x-15) = 0
...
10x^2 + 30 = 79x
10x^2 - 79x + 30 = 0
(5x-2)(2x-15) = 0
...
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