Asked by Mike
Sand is being dropped at the rate 10 metercube/min onto a conical pile. If the height of the pile is always twice the base radius, at what rate is the increasing when the pile is 8 m high?
Answers
Answered by
Steve
v = 1/3 pi r^2 (2r) = 2/3 pi r^3
at r=8,
dv/dt = 2 pi r^2 dr/dt
Now we just have to decide what "at what rate is the increasing" means
at r=8,
dv/dt = 2 pi r^2 dr/dt
Now we just have to decide what "at what rate is the increasing" means
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