Asked by Tavis
An Airplane leaves point A and attempts to fly due north at a velocity of 200 m/s. There is a crosswind of 25 m/s towards the east. How far off course is the airplane after 1 hour?
Answers
Answered by
Henry
X = 25 m/s.
Y = 200 m/s.
Tan A = Y/X = 200/25 = 8.00
A = 82.9o
Vp = Y/sin A = 200/sin82.9 = 202 m/s. =
Velocity of the plane.
d = 202m/s[82.9] * 3600s = 728,147 m. @
82.9o
Y = 200 m/s.
Tan A = Y/X = 200/25 = 8.00
A = 82.9o
Vp = Y/sin A = 200/sin82.9 = 202 m/s. =
Velocity of the plane.
d = 202m/s[82.9] * 3600s = 728,147 m. @
82.9o