Asked by Tavis
An Airplane leaves point A and attempts to fly due north at a velocity of 200 m/s. There is a crosswind of 25 m/s towards the east. How far off course is the airplane after 1 hour?
Answers
Answered by
Henry
X = 25 m/s.
Y = 200 m/s.
Tan A = Y/X = 200/25 = 8.00
A = 82.9o
Vp = Y/sin A = 200/sin82.9 = 202 m/s. =
Velocity of the plane.
d = 202m/s[82.9] * 3600s = 728,147 m. @
82.9o
Y = 200 m/s.
Tan A = Y/X = 200/25 = 8.00
A = 82.9o
Vp = Y/sin A = 200/sin82.9 = 202 m/s. =
Velocity of the plane.
d = 202m/s[82.9] * 3600s = 728,147 m. @
82.9o
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.