Asked by Thania
                A Jet airplane leaves an airport traveling at a steady rate of 600km/h. another jet leaves  the same airport 3/4h later traveling at 800km/h in the same derection. how long will the 2nd jet take to overtake the first?
            
            
        Answers
                    Answered by
            drwls
            
    The equations for the distance travlled by the two planes are
X1 = 600 (t + 0.75) and
X2 = 800 t
where t is the time after the second plane leaves.
Set X1 = X2 to find the time t when Jet 2 overtakes Jet 1
800 t = 600 t + 450
200 t = 450
t = ? hours
    
X1 = 600 (t + 0.75) and
X2 = 800 t
where t is the time after the second plane leaves.
Set X1 = X2 to find the time t when Jet 2 overtakes Jet 1
800 t = 600 t + 450
200 t = 450
t = ? hours
                    Answered by
            Thania
            
    i don't really get what you just said
    
                    Answered by
            drwls
            
    What part don't you understand?
X1 is the distance travelled by the first car to leave. X2 is the distance travlled by the second car to leave.
I left you the last step to solve.
t = 450/200 = 2.25 hours is the answer
    
X1 is the distance travelled by the first car to leave. X2 is the distance travlled by the second car to leave.
I left you the last step to solve.
t = 450/200 = 2.25 hours is the answer
                    Answered by
            Anonymous
            
    Omg im doung this exact problem in my math hw rn😂
    
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