Asked by Thania
A Jet airplane leaves an airport traveling at a steady rate of 600km/h. another jet leaves the same airport 3/4h later traveling at 800km/h in the same derection. how long will the 2nd jet take to overtake the first?
Answers
Answered by
drwls
The equations for the distance travlled by the two planes are
X1 = 600 (t + 0.75) and
X2 = 800 t
where t is the time after the second plane leaves.
Set X1 = X2 to find the time t when Jet 2 overtakes Jet 1
800 t = 600 t + 450
200 t = 450
t = ? hours
X1 = 600 (t + 0.75) and
X2 = 800 t
where t is the time after the second plane leaves.
Set X1 = X2 to find the time t when Jet 2 overtakes Jet 1
800 t = 600 t + 450
200 t = 450
t = ? hours
Answered by
Thania
i don't really get what you just said
Answered by
drwls
What part don't you understand?
X1 is the distance travelled by the first car to leave. X2 is the distance travlled by the second car to leave.
I left you the last step to solve.
t = 450/200 = 2.25 hours is the answer
X1 is the distance travelled by the first car to leave. X2 is the distance travlled by the second car to leave.
I left you the last step to solve.
t = 450/200 = 2.25 hours is the answer
Answered by
Anonymous
Omg im doung this exact problem in my math hw rn😂