at t = 0
xA = -20 , dxA/dt = -24
yA = 0, dyA/dt = 0
xB = 0, dxB/dt=0
yB = 0 , dyB/dt = 25
Dx = differnce in x location
= 20 + 24 t
Dy = difference in y location
= 25 t
distance = (Dx^2+Dy^2)^.5
distance = [ 400+480t+576t^2+ 625t^2 ]^.5
= [1201 t^2 + 480 t + 400 ]^.5
d distance/dt = .5[2402t - 480]/distance
if t = 3
d distance/dt = just put in 3 for t
At noon, ship A is 20 nautical miles due west of ship B. Ship A is sailing west at 24 knots and ship B is sailing north at 25 knots. How fast (in knots) is the distance between the ships changing at 5 PM?
I have tried multiple times but keep getting confused.
1 answer
1 answer