A 55 uL of hexane is injected in a mass spectrometer. how many protons are in the 55 uL injection? (density Hexane= 0.6548 g/mL)

Answer 1

hexane is 86 g/mol

we have 55 uL *.6548 *10^-3 g/uL
= 36*10^-3 g

36*10^-3/86
=4.2 * 10^-4 mol

* 6*10^23 = 2.51*10^20 molecules of hexane

now just add up the protons in a molecule and divide. It is C6H14
C has 6 each and H has 1 each

Answer 2

What about microliter conversion to ml?

Answer 3

It is there

0.6548 g/mL *10^-3 mL/ uL
=.6548 *10^-3 g/uL