A given sample of a xenon fluoride compound contains molecules of the type XeFn where n is some whole number. Given that 9.03 × 1020 molecules of XeFn weighs 0.368 g, determine the value for n in the formula.

Answer 1

Xe = 131 g/mol
F = 19 g/mol
so XeFn = (131 + 19 n) g/mol
or
(131+19n)g / 6*10^23 molecules
but this stuff is
.368 g/9.03*10^20 molecules
.368/9.03*10^20 = (131+19n) /6*10^23
131+19 n = 244.5 g/mol
19 n = 113.5
n = 6
so
XeF6