Asked by Maxine
A Volkswagen runs straight off a cliff. The Volkswagen is traveling at a speed of 39.0 m/s when it leaves the road. If the cliff is 16.0 m high, how far horizontally does the car travel before it smashes into the ground below?
Answers
Answered by
Henry
Xo = 39.0 m/s.
h = 0.5g*t^2 = 16 m.
4.9t^2 = 16
t^2 = 3.27
Tf = 1.81 s. = Fall time.
Dx = Xo*Tf = 39m/s * 1.81s = 70.5 m.
h = 0.5g*t^2 = 16 m.
4.9t^2 = 16
t^2 = 3.27
Tf = 1.81 s. = Fall time.
Dx = Xo*Tf = 39m/s * 1.81s = 70.5 m.