Hi! I need help finding the derivative of this function.

f(x)= ln [(x(x-1))/(x-2)]

Thank you.

2 answers

f(x)= ln[(x(x-1))/(x-2)]
f(x)= ln(x(x-1)-ln(x-2)
f(x)= ln(x)+ln(x-1)-ln(x-2)
f'(x)=1/x+1/(x-1)+1/(x-2)
Thanks Sarah!
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