f(x)= ln[(x(x-1))/(x-2)]
f(x)= ln(x(x-1)-ln(x-2)
f(x)= ln(x)+ln(x-1)-ln(x-2)
f'(x)=1/x+1/(x-1)+1/(x-2)
Hi! I need help finding the derivative of this function.
f(x)= ln [(x(x-1))/(x-2)]
Thank you.
2 answers
Thanks Sarah!