Asked by J.R.
how many moles of oxygen are there in 50.0 grams of KClO3?
Given: 50.0 g KClO3
Find: ? mol O
K= 39.10 g/mol
Cl= 35.45 g/mol
O= (16.00)x3= 48.00 g/mol
Total: 122.55 g/mol KClO3
50.0 g KClO3 x 1 mol KClO3/122.55 g/mol KClO3=0.408 mol KClO3
0.408 mol KClO3 x 3(oxygen)=1.22 moles O
Given: 50.0 g KClO3
Find: ? mol O
K= 39.10 g/mol
Cl= 35.45 g/mol
O= (16.00)x3= 48.00 g/mol
Total: 122.55 g/mol KClO3
50.0 g KClO3 x 1 mol KClO3/122.55 g/mol KClO3=0.408 mol KClO3
0.408 mol KClO3 x 3(oxygen)=1.22 moles O
Answers
Answered by
DrBob222
I agree
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