Asked by mike
how many moles of oxygen are required for the combustion of 25.5 g of magnesium
Answers
Answered by
bobpursley
write the balanced equation:
2Mg+O2>>2MgO So according to the equation, figure the moles of Mg (25.5/atomicmassMg), then half that is required number of moles of O2.
2Mg+O2>>2MgO So according to the equation, figure the moles of Mg (25.5/atomicmassMg), then half that is required number of moles of O2.
Answered by
DrBob222
Here is a step by step example of how to work stoichiometry problems.
http://www.jiskha.com/science/chemistry/stoichiometry.html
http://www.jiskha.com/science/chemistry/stoichiometry.html
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