Question

Suppose the incident sunlight at ground level has a power density of
0.87 kW m−2 at noon. What is the maximum rate of loss of water from a lake
of area 1.0 ha? (1 ha = 104 m2.) Assume that all the radiant energy is absorbed.


any ideas on how do i get through with this?

Answer 1

What about 0.87 kW/m^2 x 104 m^2 = ?kW.
Change that to J/s = x J/s
Hvap in J/g x ?g = x J/s
Solve for ?g and that will be grams H2O lost/second.
Check that.