Asked by Iworlock
If a 1500 kg car stopped from an in 5.6 seconds with an applied force of 5000 N, how fast was it initially traveling?
Answers
Answered by
Henry
a = F/m = -5000/1500 = -3.33 m/s^2
V = Vo + a*t = 0
Vo = -a*t = -(-3.33)*5.6 = 18.67 m/s.
V = Vo + a*t = 0
Vo = -a*t = -(-3.33)*5.6 = 18.67 m/s.
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