Asked by NOEL
experiments show that radium disintegrates at a rate proportional to the amount of radium present at the moment . if half life is 1590 years what percentage will disappear in one year?
Answers
Answered by
bobpursley
A(t)=Ao*(1/2)^(t/1590)
A(t)/Ao=.5^1/1590 =
put this in the google search window:
.5^1/1590 =
A(t)/Ao=.5^1/1590 =
put this in the google search window:
.5^1/1590 =
Answered by
Steve
You will probably like the answer better if you enter .5^(1/1590) ...
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