Asked by sherry
A boy of height 95 cm is walking away from base of a lamp post at a speed of 1.5 m/s.If the lamp post is 3.8 m above the ground, find the length of his shadow after 5 seconds.
Answers
Answered by
Steve
Assuming he started at the pole, after 5 seconds he is 7.5 m away.
So, if the shadow has length s, use similar triangles to get
(s+7.5)/3.8 = s/0.95
Now just solve for s.
So, if the shadow has length s, use similar triangles to get
(s+7.5)/3.8 = s/0.95
Now just solve for s.
Answered by
Pre
(x+7.5)/3.8=x/0.95
3.8x=0.95(x+7.5)
3.8x=0.95x+7.125
3.8x-0.95x=7.125
2.85x=7.125
285x/100=7125/1000
x=7125*2850
x=2.5
3.8x=0.95(x+7.5)
3.8x=0.95x+7.125
3.8x-0.95x=7.125
2.85x=7.125
285x/100=7125/1000
x=7125*2850
x=2.5
Answered by
Kajal tiwari
Question m kuch idea nhi h
Answered by
Kajal tiwari
Nice solution
Answered by
Deepali
Thnx
Answered by
achsa biju
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Answered by
dadawdadaw
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Answered by
Anonymous
not a good solution
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