Question

Tv: 57 in; Height: 30 in ; width____ a^2+b^2=c^2

Answer 1

Theater Screen: 76 ft. Height: 30 ft; Width: a^2+b^2=c^2

Answer 2

To find the width of the TV, we can use the Pythagorean theorem, which states that in a right-angled triangle, the square of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides.

Let the width of the TV be represented by "a" and the height be represented by "b". The diagonal of the TV is given as 57 inches, which is the hypotenuse (c).

Using the Pythagorean theorem, we have:

a^2 + b^2 = c^2

a^2 + 30^2 = 57^2

a^2 + 900 = 3,249

a^2 = 3,249 - 900

a^2 = 2,349

Taking the square root of both sides to solve for "a", we get:

a = √2349

a ≈ 48.46 inches

Therefore, the width of the TV is approximately 48.46 inches.

Answer 3

To find the width of the theater screen, we can use the Pythagorean theorem, which states that in a right-angled triangle, the square of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides.

Let the width of the theater screen be represented by "a" and the height be represented by "b". The diagonal of the screen is given as 76 feet, which is the hypotenuse (c).

Using the Pythagorean theorem, we have:

a^2 + b^2 = c^2

a^2 + 30^2 = 76^2

a^2 + 900 = 5,776

a^2 = 5,776 - 900

a^2 = 4,876

Taking the square root of both sides to solve for "a", we get:

a = √4876

a ≈ 69.9 feet

Therefore, the width of the theater screen is approximately 69.9 feet.