Asked by Ashley
d(x,y)={ 1 if x does not equal y
0 if x=y
Prove that d satisfies the axioms of a metric.
clearly it satisfies d(x,y) existing in the reals, and d(x,y)>=0 and d(x,y)=0 iff x=y. why I don't know is triangle inequality and d(x,y)=d(y,x).
0 if x=y
Prove that d satisfies the axioms of a metric.
clearly it satisfies d(x,y) existing in the reals, and d(x,y)>=0 and d(x,y)=0 iff x=y. why I don't know is triangle inequality and d(x,y)=d(y,x).
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