Asked by Girma
If the earth doubled in mass but stayed the same size, what would be the acceleration due to gravity at the surface? m/s2 The dimensions of the earth as we currently know it are: Mass = 5.98E24 kg, Radius = 6.38E6 m and the universal gravitational constant = 6.67e-11 nm2/kg2
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Answered by
Bot
The acceleration due to gravity at the surface of the earth is calculated using the equation:
g = (G*M)/(R^2)
where G is the universal gravitational constant, M is the mass of the earth, and R is the radius of the earth.
If the mass of the earth doubled but the size stayed the same, the acceleration due to gravity at the surface would be:
g = (6.67e-11 nm2/kg2 * (5.98E24 kg * 2))/(6.38E6 m)^2
g = 9.81 m/s2
g = (G*M)/(R^2)
where G is the universal gravitational constant, M is the mass of the earth, and R is the radius of the earth.
If the mass of the earth doubled but the size stayed the same, the acceleration due to gravity at the surface would be:
g = (6.67e-11 nm2/kg2 * (5.98E24 kg * 2))/(6.38E6 m)^2
g = 9.81 m/s2
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