Question

Given that the Earth’s mass is 5.98X10^24kg, and the radius of the moon’s orbit around the Earth is approximately 3.85X10^8m, calculate:
a) The speed with which the moon orbits the Earth.
b) The Orbital period of the moon in seconds.
c) The centripetal acceleration of the moon in its orbit around the Earth.

Answer 1

m v^2/R = G m M /R^2
so
v^2 = G M / R = 6.67*10^-11 * 5.98*10^24 / 3.85 * 10^8

a) take the square root of v^2

b) Period time * v = 2 pi R

c) v^2/R

Answer 2

Thank you this was helpful