Asked by Danielle
A professor orders 250 mL of house coffee at precisely 95°C. She then adds enough milk at 10°C to drop the temperature of the coffee to exactly 90° C.
Calculate the amount of milk (in mL) the professor must add to reach this temperature. Assume that the coffee and milk have the same specific heat capacity: 4.184 J/(g × °C). Assume that they also have the same density: 1.0 g/mL.
Calculate the amount of milk (in mL) the professor must add to reach this temperature. Assume that the coffee and milk have the same specific heat capacity: 4.184 J/(g × °C). Assume that they also have the same density: 1.0 g/mL.
Answers
Answered by
DrBob222
mass in grams = mL milk
mass in grams = mL coffee
heat lost by coffee + heat gained by milk = 0
[mass coffee x specific heat coffee x (Tfinal-Tinitial)] + [mass milk x specific heat milk x (Tfinal-Tinitial)] = 0
Substitute the numbers and solve for mass milk in grams which = mL milk.
mass in grams = mL coffee
heat lost by coffee + heat gained by milk = 0
[mass coffee x specific heat coffee x (Tfinal-Tinitial)] + [mass milk x specific heat milk x (Tfinal-Tinitial)] = 0
Substitute the numbers and solve for mass milk in grams which = mL milk.
Answered by
Anonymous
34
Answered by
T
41.8
Answered by
Confused
19.3
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