The problem si
209/83bi+64/28NI=272/111Rg+1/0n
How to calculate the energy change in J/mol reactants?
AMU amounts:
Bi=208.980384
Ni= 63.927969
Rg=272.1535
What I have done is
1. subtract products from reactants.
2. multiply the result by 1.66054x10^-27kg
3. multiply that by 8.98x10^16 (which is c^2 in e=mc^2
4. multiply that result by 6.022x10^23
The answer is 1.03x10^11. But I am not getting that.
can someone explain how to do this problem?