Asked by Pao
Find an equation of the circle with its center at (3,2) that is tangent to the positive x-axis.
Answers
Answered by
Steve
clearly the radius is 2, since the center is at y=2.
So, the equation is
(x-3)^2 + (y-2)^2 = 4
So, the equation is
(x-3)^2 + (y-2)^2 = 4
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