Find the value of in10 and in5
multiply the value of in10 wit the varables in the brackets
collect the like terms i.e live the varable with the x term on the left hand side and the others on the right
then solve for x from there.
Goodluck
10e^(3x-7)= 5
So what I've done is rewritten it as:
(3x-7)ln10e = ln5
Now I'm a little lost as to what to do next...
2 answers
Your start was incorrect...
the exponent does not apply to the 10, only to the base of e
so ...
e^(3x-7) = 5/10= .5
now take ln of both sides
(3x-7) ln e = ln .5 , but ln e = 1
3x-7 = ln .5
3x = 7 + ln .5
x = (7 + ln .5)/3 , and it is button-pushing time
the exponent does not apply to the 10, only to the base of e
so ...
e^(3x-7) = 5/10= .5
now take ln of both sides
(3x-7) ln e = ln .5 , but ln e = 1
3x-7 = ln .5
3x = 7 + ln .5
x = (7 + ln .5)/3 , and it is button-pushing time
1 answer