Asked by Lucy
Please could someone advise me on how to write a balanced equation for the breakdown off H2SeO3.
The solution is dissolved in water and conducts electricity. I know the charged ion present is H+ I am struggling to work it out and indentify the other ion formed, other than it is a negative charge. I would be very grateful if someone could help me out.
H2SeO3 + 2H2O ==> 2H3O^+ + SeO3^-2 OR
if you want to omit the water.
H<sub>2</sub>SeO<sub>3 (aq)</sub> ==> 2H<sup>+</sup><sub>(aq)</sub> + SeO3<sup>=</sup><sub>(aq)</sub>
I hope this looks ok.
Thank you very much for your time DrBob222.
I attempted it myself and came out with
the same thing, just lacked the confidence to believe I had it right, at least I have it confirmed.
Why not use B6 instead of cheating?
The solution is dissolved in water and conducts electricity. I know the charged ion present is H+ I am struggling to work it out and indentify the other ion formed, other than it is a negative charge. I would be very grateful if someone could help me out.
H2SeO3 + 2H2O ==> 2H3O^+ + SeO3^-2 OR
if you want to omit the water.
H<sub>2</sub>SeO<sub>3 (aq)</sub> ==> 2H<sup>+</sup><sub>(aq)</sub> + SeO3<sup>=</sup><sub>(aq)</sub>
I hope this looks ok.
Thank you very much for your time DrBob222.
I attempted it myself and came out with
the same thing, just lacked the confidence to believe I had it right, at least I have it confirmed.
Why not use B6 instead of cheating?
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