Asked by Kimmie
Find the maximum and minimum value of the quadratic function g(x) = 2x^2 + 6x + 3
Answers
Answered by
Steve
Since it is a parabola which opens upward, there is no maximum value.
g(x) = 2(x + 3/2)^2 - 3/2
so its minimum is -3/2
g(x) = 2(x + 3/2)^2 - 3/2
so its minimum is -3/2
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