Asked by Kasey

Find the minimum or maximum value of f(x)=−0.25x2+4x−18
Answered by Steve
recall that the vertex of the parabola

ax^2+bx+c

is at x = -b/2a

So, your maximum is at x = 4/.5 = 8

now just find f(8)
Answered by Jordan
Sow steps for 5x - 3y equals 0 to determine if this is a direct variation
Answered by Jordan
Show steps for 5x - 3y equals 0 to determine if this is a direct variation
Answered by Cole
Find the minimum or maximum value of f(x)=−0.25x2+4x−18.
Answered by Ed
This was wrong
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