Asked by chiamaka
⦁ Find the resultant vector (magnitude and direction) for the sum of:
vector A which has magnitude 365 N at 48° south of west,
vector B which has magnitude 224 N at 26° south of east, and
vector C which has magnitude 488 N at 12° west of north.
Express the direction of the resultant relative to due west.
vector A which has magnitude 365 N at 48° south of west,
vector B which has magnitude 224 N at 26° south of east, and
vector C which has magnitude 488 N at 12° west of north.
Express the direction of the resultant relative to due west.
Answers
Answered by
Henry
F = 365N[228o]CCW+224N[334o]CCW+488N [102o]CCW.
Fx=365*Cos228 + 224*Cos334 + 488*cos102
= -144.4 N.
Fy=365*sin228 + 224*sin334 + 488*sin102
= 107.9 N.
Tan Ar = Fy/Fx = 107.9/-144.4 = -0.74718
Ar = -36.8o = Reference angle.
A = -36.8 + 180 = 143.2o CCW = 36.8o N.
of W.
F = Fx/Cos A = -144.4/Cos143.2 = 180.3 N
[143.2]CCW = 180.3N[36.8o] North of West.
Fx=365*Cos228 + 224*Cos334 + 488*cos102
= -144.4 N.
Fy=365*sin228 + 224*sin334 + 488*sin102
= 107.9 N.
Tan Ar = Fy/Fx = 107.9/-144.4 = -0.74718
Ar = -36.8o = Reference angle.
A = -36.8 + 180 = 143.2o CCW = 36.8o N.
of W.
F = Fx/Cos A = -144.4/Cos143.2 = 180.3 N
[143.2]CCW = 180.3N[36.8o] North of West.
Answered by
Vafee Kelleh
fire
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.