Question
Find the arc length of one arch of the sine curve.
I started it by doing y=sinx, y'=cosx
arc length= integral of sqrt(1+cos^2x)dx from pi/2 to 3pi/2
but I don't know how to integrate that! Thank you!
I started it by doing y=sinx, y'=cosx
arc length= integral of sqrt(1+cos^2x)dx from pi/2 to 3pi/2
but I don't know how to integrate that! Thank you!
Answers
Damon
yuuk!
http://www.wolframalpha.com/input/?i=int+%281+%2B+cos^2x%29^.5+dx
http://www.wolframalpha.com/input/?i=int+%281+%2B+cos^2x%29^.5+dx
Damon
by the way I think you want arch from 0 to pi which Wolfram gives as 3.8 something