Asked by jackey
An arch is in the form of a Semi-Ellipse. It is 40 feet wide at the base and has a height of 18 feet. How wide is the
arch at a height of 15 feet above the base? Nearest tenth.
arch at a height of 15 feet above the base? Nearest tenth.
Answers
Answered by
oobleck
so you have
a = 20
b = 18
so the equation is
x^2/400 + y^2/324 = 1
When y=15, x = 10√11/3
so the arch is 20√11/3 wide at that point
a = 20
b = 18
so the equation is
x^2/400 + y^2/324 = 1
When y=15, x = 10√11/3
so the arch is 20√11/3 wide at that point
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