Asked by Joe
A cauterizer, used to stop bleeding in surgery, puts out 2.30 mA at 14.0 kV. What is its power output?
What is the resistance of the path?
What is the resistance of the path?
Answers
Answered by
bobpursley
power=Voltage*current=14E3*2.3E-3 watts
Answered by
Joe
I got the first part of the question right.
It was 32.2 W
How would I do the second part?
It was 32.2 W
How would I do the second part?
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