Question

A cauterizer, used to stop bleeding in surgery, puts out 2.30 mA at 14.0 kV. What is its power output?

What is the resistance of the path?

Answer 1

power=Voltage*current=14E3*2.3E-3 watts

Answer 2

I got the first part of the question right.
It was 32.2 W

How would I do the second part?