Asked by Joe

A cauterizer, used to stop bleeding in surgery, puts out 2.30 mA at 14.0 kV. What is its power output?

What is the resistance of the path?
Answered by bobpursley
power=Voltage*current=14E3*2.3E-3 watts
Answered by Joe
I got the first part of the question right.
It was 32.2 W

How would I do the second part?
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