Question

Two forces are applied to a car in an effort to move it, as shown in the following figure (cannot attach picture), where F1 = 416 N, 10 degrees to the left of north and F2 = 356 N, 30 degrees to the right of north.

What is the sum of these two forces acting on the car?
Magnitude=
Direction=



I found the following:
F1x=416*sin(10)+-226.3128
F2x=356*sin(30)=-351.7393
F1x+F2x=-578.0521

and
F1y=416*cos(10)=-349.0538
F2y=356*cos(30)=54.9135
F1y+F2y=-294.1403

I tried finding directing using:
Tan=-294.1403/-578.0521=0.50885
So direction should be =26.969 but was wrong.
I'm not sure where to go from here

Answer 1

x is generally taken positive to the right (east)
F1x= -416 sin 10 = -72.2
F2x = 356 sin 30 = 178
so Fx = 106

F1y = 416 cos 10 = 410
F2y = 356 cos 30 = 308 We must be operating on different number systems :(
Fy = 718

tan angle up from x axis (east)
= 718/106 =
so angle up from east = 81.6 deg
so angle clockwise from north = 8.4 degrees right from north

magnitude = sqrt (106^2+718^2)
= 726