Asked by Shant
Two forces are applied to a tree stump to pull it out of the ground. Force A has a magnitude of 2880 newtons (N) and points 42.0 ° south of east, while force B has a magnitude of 4360 N and points due south. Using the component method, find the (a) magnitude and (b) direction of the resultant force A + B that is applied to the stump. Specify the direction as a positive angle with respect to due east.
Answers
Answered by
Damon
east components
2880 cos 42 = 2140
south components
2880 sin 42 + 4360 = 6287
magnitude = sqrt (2140^2+6287^2)
tan (angle) = 6287/2140
2880 cos 42 = 2140
south components
2880 sin 42 + 4360 = 6287
magnitude = sqrt (2140^2+6287^2)
tan (angle) = 6287/2140
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.