Asked by Student
Find the equation for the exponential function that passes through the pairs of points given. Through (-1,2) and (3,1).
I don't know if this is the right way to work this or what the next step is i am just very confused. Please help, thank you!
y=Ab^x
2=Ab^1
1=Ab^3
2=(1/b^3)=b^-3
2=b^-3(b^-3)
2=b^-6
Now
I don't know if this is the right way to work this or what the next step is i am just very confused. Please help, thank you!
y=Ab^x
2=Ab^1
1=Ab^3
2=(1/b^3)=b^-3
2=b^-3(b^-3)
2=b^-6
Now
Answers
Answered by
Steve
Ahem
2 = Ab^-1 = A/b, so A = 2b
1 = Ab^3 = 2b^4
b = (1/2)^1/4
2 = A*2^(1/4)
A = 2^(3/4)
y = 2^(3/4) (1/2)^(x/4)
or
y = ∜(8/2^x)
2 = Ab^-1 = A/b, so A = 2b
1 = Ab^3 = 2b^4
b = (1/2)^1/4
2 = A*2^(1/4)
A = 2^(3/4)
y = 2^(3/4) (1/2)^(x/4)
or
y = ∜(8/2^x)
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