Asked by Francisco Ayala
A chemist has 10% acid solution and 60% acid solution. HOW many liters of each solution does the chemist need to make 200 L of a solution that is 50% acid?
Answers
Answered by
Reiny
amount of 10% solution ---- x L
amount of 60% solution ---- 200-x L
.1x + .6(200-x) = .5(200)
times 10
x + 6(200-x) = 5(200)
x + 1200 - 6x = 1000
-5x = -200
x = 40
check:
.1(40) + .6(160)
= 4+96
= 100 which is 50% of 200L
amount of 60% solution ---- 200-x L
.1x + .6(200-x) = .5(200)
times 10
x + 6(200-x) = 5(200)
x + 1200 - 6x = 1000
-5x = -200
x = 40
check:
.1(40) + .6(160)
= 4+96
= 100 which is 50% of 200L
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.