Question
A chemist has 10% acid solution and 60% acid solution. HOW many liters of each solution does the chemist need to make 200 L of a solution that is 50% acid?
Answers
Reiny
amount of 10% solution ---- x L
amount of 60% solution ---- 200-x L
.1x + .6(200-x) = .5(200)
times 10
x + 6(200-x) = 5(200)
x + 1200 - 6x = 1000
-5x = -200
x = 40
check:
.1(40) + .6(160)
= 4+96
= 100 which is 50% of 200L
amount of 60% solution ---- 200-x L
.1x + .6(200-x) = .5(200)
times 10
x + 6(200-x) = 5(200)
x + 1200 - 6x = 1000
-5x = -200
x = 40
check:
.1(40) + .6(160)
= 4+96
= 100 which is 50% of 200L