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solution of 0.1molar NH4OH and 0.1 NH4CL ph=9.25 calculate kb for NH4OH?
11 years ago

Answers

DrBob222
pH = pKa + log (base)/(acid)
Substitue and solve for pKa, then convert pKa to pKb, then to Kb
pKa + pKb = pKw = 14.
and pKb = -logKb
11 years ago
ankita
i also need the answer
8 years ago
Anonymous
4.75
7 years ago

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