Asked by ghenny
Please solve these using the quadratic formula:
1. 3x^2-4(x-2)=0
2.a^2+2(a++5)=0
3.x^2-3(2x+3)=0
Thank you ^____^
1. 3x^2-4(x-2)=0
2.a^2+2(a++5)=0
3.x^2-3(2x+3)=0
Thank you ^____^
Answers
Answered by
Steve
Tell you what. I'll solve one, and you can try the others. Post your work if you get stuck.
x^2-3(2x+3)=0
x^2-6x-9 = 0
x = (6±√(36+36))/2 = (6±6√2)/2 = 3±3√2
x^2-3(2x+3)=0
x^2-6x-9 = 0
x = (6±√(36+36))/2 = (6±6√2)/2 = 3±3√2
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