Asked by Anonymous

A kangaroo jumps straight up to a vertical height of 1.19m, how long was it in the air before returning on earth
Answered by Henry
h = 0.5g*t^2 = 1.19 m.
4.9t^2 = 1.19
t^2 = 0.243
Tf = 0.493 s. = Fall time.

Tr = Tf = 0.493 s. = Rise time.

Tr+Tf = 0.493 + 0.493 = 0.986 s. = Time
in air.
Answered by Michael
why did you multiply it by 2